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Unformatted text preview: if one mesh current is assumed clockwise and the other assumed
anticlockwise, although this is permissible. (3.15) which can be solved to obtain the mesh currents i1 and i2 . We are at liberty
to use any technique for solving the simultaneous equations. According
to Eq. (2.12), if a circuit has n nodes, b branches, and l independent
loops or meshes, then l = b − n + 1. Hence, l independent simultaneous
equations are required to solve the circuit using mesh analysis.
Notice that the branch currents are different from the mesh currents
unless the mesh is isolated. To distinguish between the two types of
currents, we use i for a mesh current and I for a branch current. The
current elements I1 , I2 , and I3 are algebraic sums of the mesh currents.
It is evident from Fig. 3.17 that | v v I1 = i1 , | I2 = i2 , e-Text Main Menu I3 = i1 − i2 | Textbook Table of Contents | (3.16) Problem Solving Workbook Contents 90 PART 1 DC Circuits EXAMPLE 3.5
I1 5Ω I2 For the circuit in Fig. 3.18, ﬁn...
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- Spring '12