# Notice that the branch currents are different from

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Unformatted text preview: if one mesh current is assumed clockwise and the other assumed anticlockwise, although this is permissible. (3.15) which can be solved to obtain the mesh currents i1 and i2 . We are at liberty to use any technique for solving the simultaneous equations. According to Eq. (2.12), if a circuit has n nodes, b branches, and l independent loops or meshes, then l = b − n + 1. Hence, l independent simultaneous equations are required to solve the circuit using mesh analysis. Notice that the branch currents are different from the mesh currents unless the mesh is isolated. To distinguish between the two types of currents, we use i for a mesh current and I for a branch current. The current elements I1 , I2 , and I3 are algebraic sums of the mesh currents. It is evident from Fig. 3.17 that | v v I1 = i1 , | I2 = i2 , e-Text Main Menu I3 = i1 − i2 | Textbook Table of Contents | (3.16) Problem Solving Workbook Contents 90 PART 1 DC Circuits EXAMPLE 3.5 I1 5Ω I2 For the circuit in Fig. 3.18, ﬁn...
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