The two supermeshes intersect and form a larger

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Unformatted text preview: s the constraint equation necessary to solve for the mesh currents. 2. A supermesh has no current of its own. 3. A supermesh requires the application of both KVL and KCL. EXAMPLE 3.7 | v v For the circuit in Fig. 3.24, find i1 to i4 using mesh analysis. Solution: Note that meshes 1 and 2 form a supermesh since they have an independent current source in common. Also, meshes 2 and 3 form another supermesh | e-Text Main Menu | Textbook Table of Contents | Problem Solving Workbook Contents 94 PART 1 DC Circuits 2Ω i1 i1 4Ω 2Ω P i2 6Ω io 5A i2 3io i2 Figure 3.24 Q i3 8Ω i4 + 10 V − i3 For Example 3.7. because they have a dependent current source in common. The two supermeshes intersect and form a larger supermesh as shown. Applying KVL to the larger supermesh, 2i1 + 4i3 + 8(i3 − i4 ) + 6i2 = 0 or i1 + 3i2 + 6i3 − 4i4 = 0 (3.7.1) For the independent current source, we apply KCL to node P : i2 = i1 + 5 (3.7.2) For the dependent current source, we apply KCL to node Q: i2 = i3 + 3i...
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