Unformatted text preview: s the constraint equation necessary to solve for the
2. A supermesh has no current of its own.
3. A supermesh requires the application of both KVL and KCL. EXAMPLE 3.7 | v v For the circuit in Fig. 3.24, ﬁnd i1 to i4 using mesh analysis.
Note that meshes 1 and 2 form a supermesh since they have an independent
current source in common. Also, meshes 2 and 3 form another supermesh | e-Text Main Menu | Textbook Table of Contents | Problem Solving Workbook Contents 94 PART 1 DC Circuits
i1 4Ω 2Ω P
6Ω io 5A
i2 3io i2 Figure 3.24 Q i3 8Ω i4 + 10 V
− i3 For Example 3.7. because they have a dependent current source in common. The two
supermeshes intersect and form a larger supermesh as shown. Applying
KVL to the larger supermesh,
2i1 + 4i3 + 8(i3 − i4 ) + 6i2 = 0
i1 + 3i2 + 6i3 − 4i4 = 0
For the independent current source, we apply KCL to node P :
i2 = i1 + 5
For the dependent current source, we apply KCL to node Q:
i2 = i3 + 3i...
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