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Unformatted text preview: ircuit has N meshes, the meshcurrent equations
can be expressed in terms of the resistances as R1N
i1
v1
R2N i2 v2 . . = . . . . .
.
. R11
R21
.
.
. R12
R22
.
.
. ...
...
.
.
. RN 1 RN 2 . . . RN N iN (3.25) vN or simply
Ri = v (3.26) where
Rkk = Sum of the resistances in mesh k
Rkj = Rj k = Negative of the sum of the resistances in common with
meshes k and j , k = j
ik = Unknown mesh current for mesh k in the clockwise
direction
vk = Sum taken clockwise of all independent voltage sources
in mesh k , with voltage rise treated as positive
R is called the resistance matrix, i is the output vector; and v is the input
vector. We can solve Eq. (3.25) to obtain the unknown mesh currents. EXAMPLE 3.8
Write the nodevoltage matrix equations for the circuit in Fig. 3.27 by
inspection.
2A 1Ω
v1 3A  v v Figure 3.27  eText Main Menu 5 Ω v2 10 Ω 8Ω 1A 8Ω v3 4Ω v4 2Ω 4A For Example 3.8.  Textbook Table of Contents  Problem Solving Workbook Contents CHAPTER 3 Methods of Analysis 97 Solution:
The circuit in Fig. 3.27 h...
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This note was uploaded on 07/16/2012 for the course KA KA 2000 taught by Professor Bkav during the Spring '12 term at Cambridge.
 Spring '12
 bkav

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