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Unformatted text preview: =8 This is a valid equation. Thus, our check for accuracy was successful. Has the problem been solved SATISFACTORILY? If so, present the solution; if not, then return to “ALTERNATIVE solutions” and continue through the process again. This problem has been solved satisfactorily. v = 20 volts i 2 = 2 amps i1 = 1 amp i 4 = 1 amp Find I and Vab in the circuit of Figure 2.1. [2.15] Problem 2.8 i 3 = 4 amps 3Ω 10 V −+ 5Ω a I + 30 V + − Vab + − 8V − b Figure 2.1 Applying KVL to the loop, - 30 + 3 I − 10 + 5 I + 8 = 0 8 I = 32 I = 4 amps So, - Vab + 5 I + 8 = 0 Vab = 5 I + 8 = (5)(4) + 8 | v v Therefore, | Vab = 28 volts e-Text Main Menu | Textbook Table of Contents | Problem Solving Workbook Contents In Figure 2.1, solve for i1 and i 2 . Problem 2.9 V1 − + + 4V − i2 3A i1 + 2A + + − 20 V V2 12 V + − − − Figure 2.1 a b i2 3A i1 2A + − + − KCL (node a) : KCL (node b) : i1 + 3 + 2 = 0 i1 = - 5 amps i2 + 0 = 3 i 2 = 3 amps In Figure 2.1, find V1 and V2 . Problem 2.10 − V1 + + 4V − + + 20 V + − Loop 1 12 V Loop 2 − | v v V1 = - 8 volts | e-Text Main Menu | Textbook Table of Contents | V2 + − − V2 = 8 volts Problem Solving Workbook Contents SERIES AND PARALLEL RESISTORS Two or more elements are in series if they are cascaded or connected sequentially and consequently carry the same current. Two or more elements are in parallel if they are connected to the same two nodes and consequently have the same voltage across them. [2.35] Problem 2.11 following networks. Find the equivalent resistance at terminals a-b for each of the a Req R b R R R R Req a R R a R b Req R b (a) (b) (c) R a Req a 3R R R Req b (a) 3R R eq = R R + R R = (c) R eq (e) R eq = R 0 = 0 (b) (d) R eq (e) R eq v v 2R b (d) | R | RR + =R 22 = ( R + R ) ( R + R ) = 2R 2R = R 3 (3R ) R 2 9R 2 R 3 = 3R (R + R R ) = 3R R + = 3R R = = =R 3 2 2 9R 3R + R 2 2 R (3R ) 3 6R2 2 6 (R )(2R ) 3R = R 3R = = R 2R 3R = = =R 2 R + 2R 3 11 R 11 R + 3R 3 e-Text Main Menu | Textbook Table of Contents | Problem Solving Workbook Contents Therefore, R eq = 0 (a) Problem 2.12 resistor. (b), (c), (d) R eq = R 6 R 11 and (e) R eq = Give...
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