HWK 11 solution - Production Engineering PGE 362 Homework...

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Production Engineering PGE 362 Homework 11 Solution Due in lecture on Nov. 21, 2007. (1) Given the mini-frac data shown in the attached table, please estimate – (a) the ISIP (b) the fracture closure pressure (show the graph) (c) the fluid efficiency (d) the minimum required pad volume (e) the total fracture entry friction pressure as a function of rate (show the graph) (f) the minimum number of perforations open (if all of the entry friction is associated only with perforations). (g) the perforation friction and the near well bore friction as a function of rate if all of the perforations are open. Frac Design: Stage Rate (BPM) Fluid Proppant 01 – Pad 25 55,000 gal Pad none 02 – prop 25 54,000 gal ramp from 2 to 6 ppg sand 03 – prop 25 12,000 gal ramp from 6 to 7 ppg sand 04 – prop 25 12,000 gal ramp from 7 to 8 ppg sand 05 – prop 25 12,000 gal 8 ppg sand The volumes shown are clean fluid volumes, meaning they do not account for the volume of proppant added during a stage. The total proppant is 480,000 lbs. Base fluid friction pressure = 0.0023 psi/ft/BPM Base fluid density = 8.35 lb/gal Leak Off Coefficient = 0.0029 ft/sqrt(min) Formation Young’s Modulus (E) = 2,500,000 psi Perforation Data: 96 total holes shot between 6860’ and 6900’.
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This homework help was uploaded on 04/07/2008 for the course PGE 362 taught by Professor Bommer during the Spring '08 term at University of Texas at Austin.

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HWK 11 solution - Production Engineering PGE 362 Homework...

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