problem05_p124

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.124: For convenience, take the positive direction to be down, so that for the baseball released from rest, the acceleration and velocity will be positive, and the speed of the baseball is the same as its positive component of velocity. Then the resisting force, directed against the velocity, is upward and hence negative. a) b) Newton’s Second Law is then . 2 Dv mg ma - = Initially, when , 0 = v the acceleration is g , and the speed increases. As the speed increases, the resistive force increases and hence the acceleration decreases. This continues as the speed approaches the terminal speed. c) At terminal velocity, , 0 = a so
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Unformatted text preview: , t D mg v = in agreement with Eq. (5.13). d) The equation of motion may be rewritten as ). ( 2 2 2 t v v t v g dt dv-= This is a separable equation and may be expressed as , arctanh 1 or , t 2 t t 2 t 2 2 t v gt v v v dt v g v v dv = =-∫ ∫ so ( 29 . tanh t t v gt v v = Note : If inverse hyperbolic functions are unknown or undesirable, the integral can be done by partial fractions, in that , 1 1 2 1 1 t t t 2 2 t + +-=-v v v v v v v and the resulting logarithms in the integrals can be solved for ) ( t v in terms of exponentials....
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• Derivative, Hyperbolic function, speed increases, resistive force increases

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