problem06_13

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.13: Let point 1 be at the bottom of the incline and let point 2 be at the skier. 1 2 tot K K W - = 0 , 2 1 2 2 0 1 = = K mv K Work is done by gravity and friction, so f mg W W W + = tot . mgh y y mg W mg - = - - = ) ( 1 2 α μ α α μ tan / ) sin / )( cos (
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Unformatted text preview: W f-=-=-= Substituting these expressions into the work-energy theorem and solving for v gives ) tan / 1 ( 2 k + = gh v...
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