problem06_15

University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.15: a) parallel to incline: force component sin mg α = , down incline; displacement sin h α = / , down incline mgh h mg W = = ) sin / )( sin ( || α α perpendicular to incline: no displacement in this direction, so 0 = W . mgh W W W mg = + = || , same as falling height h . b) tot 2 1 W K K = - gives 2 1 2 mgh mv = and gh v 2 = , same as if had been dropped from height h . The work done by gravity depends only on the vertical displacement of the object. When the slope angle is small, there is a small force component in the direction of
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