https:www.zoology.ubc.ca:~rikblok:phys102:tutorial:tut08 - http\/www.zoology.ubc.ca\/\u02dcrikblok\/phys102\/tutorial Hint Remember charge is conserved UBC

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Text: Ch. 24: Pr. 36.Two capacitors,C 1 = 2200 pF, areconnected in series to a12.battery. The capacitorsare later disconnected from the battery and connecteddirectly to each other, positive plate to positive plate,and negative plate to negative plate. What then will bethe charge on each capacitor?Hint: Remember, charge is conserved. 0 V UBC Physics 102: Tutorial 8, July 11, 2003 – p. 1/6
Solution Q C 1 QC 2 V . UBC Physics 102: Tutorial 8, July 11, 2003 – p. 2/6
Solution, contd To find Q we replace the combination by a single capacitor with the equivalent capacitance, C eq = 1 C 1 + 1 C 2 - 1 = 1 3200 pF + 1 2200 pF - 1 = 1300 pF . This capacitor would acquire a charge Q = C eq V = (1300 pF)(12 . 0 V) = 15 . 6 nC . So that is the charge initially on each capacitor.