MATH 121 - WRITTEN EXERCISES-MODULE 1

# 15 5m 2 3r 2 m 2r 2 53 m 2 r 2 3 m 2 5

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Unformatted text preview: (4)-(z(z)+z(4)+6(z)+6(4)) (3z 2 + 12 z + 2 z + 8) − ( z 2 + 4z + 6 z + 24) (3z 2 + 14z + 8)(− z 2 − 10 z − 24) 2 z 2 + 4z − 16 2( z + 4)( z − 2) = = = = 20.) 15 − 5m 2 − 3r 2 + m 2r 2 = (5(3-m 2 ) − r 2 (3 − m 2 )) = (5 − r 2 )(3 − m 2 ) 2 2 = ( 3− m ) ( 5− r ) 28.) 9 y 2 − 18 y + 8 = (3y – 4) (3y – 2) 2 2 2 2 44.) 20 p − 100 pq + 125q = 5 ( 4p − 20 pq + 25q ) = 5(2 p − 5q )(2 p − 5q) = 5 ( 2 p − 5q ) 2 52.) 16q 2 − 25 = (4q + 5) (4q – 5) 68.) ( b + 3) 3 − 27 = ((b+3)-3((b+3) 2 + 3(b + 3) + 9) = (b + 3 − 3)((b + 3)(b + 3) + 3b + 9 + 9) = (b(b(b) + b(3) + 3(b) + 3(3) + 3b + 9 + 9) = b(b 2 + 3b + 3b + 9 + 3b + 9 + 9) = b(b 2 + 9b + 27) 2 2 80.) a 4 − 2a 2 − 48 = ( a − 8 ) ( a + 6 ) 82.) 6 ( 4z − 3) + 7 ( 4z − 3 ) − 3 = 2 = = = = ( 6u 2 + 7u − 3 ) ( 2u + 3) ( 3u − 1) �( 4z − 3) + 3�3 ( 4z − 3) − 1� 2 � � � � � ( 8 z − 6 + 3) ( 12 z − 9 − 1) 2 ( 8 z − 3) (...
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## This note was uploaded on 04/07/2012 for the course MATH 121 taught by Professor Crockett during the Spring '12 term at Thomas Edison State.

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