MATH 121 - WRITTEN EXERCISES-MODULE 1

# 20 6 y 2 11 y 4 3y2 7 y 4 22 32 3r 2 9r

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Unformatted text preview: 6 z − 5 ) 100.) 100r 2 − 169 s 2 = (10r +13s) (10r – 13s) Jimmy Morgan-MAT-121-OL-(1 Nov 09 thru 23 Jan 2010) R.5 Written Assignment 9 x + 12 3(3x ) + 3(4) 3(3 x + 4) = = ( 2 x + 3) ( x + 5) (2 x + 3)( x − 5) (2 x + 3)( x − 5) 3 (2 x + 3)( x − 5) = 0; x = − and x = 5 2 � 3� x � x − , 5� 2 � 4. 20. 6 y 2 + 11 y + 4 = 3y2 + 7 y + 4 = 22.) 32. 3r 2 9r 3 ( 2 y + 1) ( 3 y + 4 ) ( y + 1) ( 3 y + 4 ) 2 y +1 y +1 8r 3 6r 3r 2 = 6r 8r 3 9r 3 31 11 = 2� = 2� 4r 3r 4r r 1 =3 4r y2 + y − 2 y2 + 3y − 4 y2 + 3y + 2 = y 2 + 4y + 3 = 40. 52. ( y + 2 ) ( y − 1) ( y + 2 y ) ( y + 3) ( y + 4 ) ( y − 1) ( y + 2 y ) ( y + 2 ) y+3 y+4 8 3 84 35 + = + 5 p 4p 5 p 4 4p 5 32 15 = 20 p 20 p 47 = 20 p ( q ) ( −1) q q q − = − p−q q− p p − q ( q − p ) ( −1) q q − = p−q q− p 2q = p−q Jimmy Morgan-MA...
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## This note was uploaded on 04/07/2012 for the course MATH 121 taught by Professor Crockett during the Spring '12 term at Thomas Edison State.

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