D use the function p defined in part c to find the

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Unformatted text preview: e meaning of your answer in terms of water temperature. (d) Use the function P defined in part (c) to find the average value, in degrees Celsius, of P (t ) over the time interval 0 > t > 15 days. (a) Difference quotient; e.g. W a(12) x W (12)  12 W a(12) x W (12) 12 W (9)  9 W (15) 15 W (9)  9 £ 1 : difference quotient ¦ 2:¦ ¤ ¦ 1 : answer (with units) ¦ ¥ 2 °C/day or 3 W a(12) x (b) W (15) 15 1 °C/day 2 3 20 2 2(31) 2(28) 2(24) Average temperature x (c) P a(12)  10e  10 te 3 t /3 30e 4  1 °C/day or 3 2(22) 21  376.5 1 (376.5)  25.1 °C 15 t/3 £ 1 : trapezoidal method ¦ 2:¦ ¤ ¦ 1 : answer ¦ ¥ £ 1 : P a(12) (with or without units) ¦ 2:¦ ¤ ¦ 1 : interpretation ¦ ¥ t 12 0.549 °C/day This means that the temperature is decreasing at the rate of 0.549 °C/day when t = 12 days. (d) 1 15 20 15 ¨0 10te t /3 £ 1 : integrand ¦ ¦ ¦ ¦ 1 : limits and ¦ 3:¦ ¤ ¦ average value constant ¦ ¦ ¦ 1 : answer ¦ ¦ ¥ dt  25.757 °C Copyright © 2001 by College Entrance Examination Board....
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This document was uploaded on 05/03/2012.

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