{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW 2 Solution for ECE0257 - 2.2 = 1 1 = 1 1 1001 = = = 1001...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
2.2 𝑣𝑣 + = 𝑣𝑣 𝑖𝑖 × 1 𝐾𝐾 1 𝐾𝐾 + 1 𝑀𝑀 = 𝑣𝑣 𝑖𝑖 × 1 1001 𝑣𝑣 𝑜𝑜 = 𝐴𝐴𝑣𝑣 + = 𝐴𝐴𝑣𝑣 𝑖𝑖 × 1 1001 𝐴𝐴 = 1001 𝑣𝑣 𝑜𝑜 𝑣𝑣 𝑖𝑖 = 1001 × 4 2 = 2002 𝑉𝑉 𝑉𝑉 � � 2.6 𝑣𝑣 𝑐𝑐𝑐𝑐 = 1 sin(2 𝜋𝜋 ∗ 60 𝑡𝑡 ) = 1 2 ( 𝑣𝑣 1 + 𝑣𝑣 2 ) 𝑣𝑣 𝑑𝑑 = 0.01 sin(2 𝜋𝜋 ∗ 1000 𝑡𝑡 ) = 𝑣𝑣 1 −𝑣𝑣 2 𝑣𝑣 1 = 𝑣𝑣 𝑐𝑐𝑐𝑐 1 2 𝑣𝑣 𝑑𝑑 = sin(2 𝜋𝜋 ∗ 60 𝑡𝑡 ) 0.005 sin(2 𝜋𝜋 ∗ 1000 𝑡𝑡 ) 𝑣𝑣 2 = 𝑣𝑣 𝑐𝑐𝑐𝑐 + 1 2 𝑣𝑣 𝑑𝑑 = sin(2 𝜋𝜋 ∗ 60 𝑡𝑡 ) + 0.005 sin(2 𝜋𝜋 ∗ 1000 𝑡𝑡 ) D2.12 a. 𝐺𝐺 = 1 𝑉𝑉 𝑉𝑉 = 𝑅𝑅 2 𝑅𝑅 1 ⟹ 𝑅𝑅 2 = 𝑅𝑅 1 = 10 𝑘𝑘Ω b. 𝐺𝐺 = 2 𝑉𝑉 𝑉𝑉 = 𝑅𝑅 2 𝑅𝑅 1 ⟹ 𝑅𝑅 1 = 10 𝑘𝑘Ω , 𝑅𝑅 2 = 20 𝑘𝑘Ω c. 𝐺𝐺 = 0.5 𝑉𝑉 𝑉𝑉 = 𝑅𝑅 2 𝑅𝑅 1 ⟹ 𝑅𝑅 1 = 20 𝑘𝑘Ω , 𝑅𝑅 2 = 10 𝑘𝑘Ω d. 𝐺𝐺 = 100 𝑉𝑉 𝑉𝑉 = 𝑅𝑅 2 𝑅𝑅 1 ⟹ 𝑅𝑅 1 = 10 𝑘𝑘Ω , 𝑅𝑅 2 = 1 𝑀𝑀Ω
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
Background image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}