problem06_35

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.35: a) The static friction force would need to be equal in magnitude to the spring force, kd mg = μ s or 76 . 1 ) s / m 80 . 9 )( kg 100 . 0 ( ) m 086 . 0 )( m / N 0 . 20 ( s 2 = = μ , which is quite large. (Keeping extra figures in the intermediate calculation for d gives a different answer.) b) In Example 6.6, the relation 2 1 2 k 2 1 2 1 mv kd mgd = + μ was obtained, and d was found in terms of the known initial speed 1 v . In this case, the condition on d is that the static friction force at maximum extension just balances the
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Unformatted text preview: spring force, or mg kd s = . Solving for 2 1 v and substituting, )), 47 . )( 60 . ( 2 ) 60 . (( ) m / N . 20 ( ) s / m 80 . 9 )( kg 10 . ( ) 2 ( 2 2 2 2 2 k s 2 s 2 s k 2 s k 2 2 1 + = + = + = + = k mg k mg g k mg m k d gd d m k v from which s / m 67 . 1 = v ....
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