Exam3Solution-EP1-S08

Exam3Solution-EP1-S08 - Engineering Physics 1 (Phys. 213)...

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9 Engineering Physics 1 (Phys. 213) Exam 3, Mar. 14 th , 2008 (O’Shea) Name __________________________________ Instructions: Please Read! This is a closed book, closed notes exam. This exam contains multiple-choice questions and problems. For each multiple-choice question, circle the letter of the best response. For problems, you need to show your work in a professional manner and write the final numerical answer with the proper unit in the space shown. Numerical answers without supporting calculations will receive zero credit. Partial credit is available only if your work is clear. 1. Academic honesty statement. This exam will NOT be marked unless you sign the academic honesty statement below. Your signature indicates that you have read , understood , and complied with the meaning of this statement. On my honor as a student I have neither given nor received unauthorized aid on this assignment. Sign your name:__________________________________________________________ 2. (1 point) Circle your Studio instructor/hour: Lynch /TU 9:30 Matloob /TU 11:30 Regehr /TU 1:30 O’Shea/WF 7:30 Lynch /WF 9:30 Page total: /1
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10 3. (8 pts) Two children are playing a game in which they try to hit a small box on the floor with a marble fired from a spring-loaded gun that is mounted on a table. The target box is horizontal distance D = 2.20 m from the edge of the table as shown. Bobby compresses the spring 1.10 cm, but the center of the marble lands at distance 1.93 m from the edge of the table. How far should Rhoda compress the spring to score a direct hit? Assume that neither the spring nor the ball encounters friction in the gun. For Rhoda, want to choose the spring compression x so that distance D = 2.20 m To find initial velocity of ball: m k x v mv kx / 0 2 0 2 1 2 2 1 = = Horizontal distance travelled by ball t v D 0 = Therefore m k tx D / = For Bobby distance (horizontal) is D 1 = 1.93 m and spring compression is x 1 = 1.10 cm m k tx D / 1 1 = Now divide the first equation by the second equation to get x cm 25 . 1 / / 1 1 1 1 = = = x D D x m k tx m k tx D D 4. (6 pts) A block is sliding on a horizontal surface with an initial velocity of 2 m/s. The coefficient of kinetic friction is 0.4. How far does the block slide before coming to rest?
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Exam3Solution-EP1-S08 - Engineering Physics 1 (Phys. 213)...

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