problem06_40

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 6.40: a) From Eq. (6.14), with dl = Rd , F cos dl = 2wR cos d = 2wR sin 0 . 0 In an equivalent geometric treatment, when F is horizontal, F dl = Fdx , and the total work is F = 2w times the horizontal distance, in this case (see Fig. 6.20(a)) R sin 0 , 2w giving the same result. b) The ratio of the forces is w tan 0 = 2 cot 0 . P1 W = P2 0 c) 2 wR sin 0 sin 0 =2 = 2 cot 0 . wR (1 - cos 0 ) (1 - cos 0 ) 2 ...
View Full Document

This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online