problem06_41

University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.41: a) The initial and final (at the maximum distance) kinetic energy is zero, so the positive work done by the spring, 2 ) 2 / 1 ( kx , must be the opposite of the negative work done by gravity, θ mgL sin - , or cm. 7 . 5 ) m / N 640 ( 0 . 40 sin ) m 80 . 1 )( s / m 80 . 9 )( kg 0900 . 0 ( 2 sin 2 2 = ° = = k θ mgL x At this point the glider is no longer in contact with the spring. b) The intermediate calculation of the initial compression can be avoided by considering that between the
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Unformatted text preview: point 0.80 m from the launch to the maximum distance, gravity does a negative amount of work given by J 567 . . 40 sin ) m 80 . m 80 . 1 )( s / m 80 . 9 )( kg 0900 . ( 2-= °--, and so the kinetic energy of the glider at this point is 0.567 J. At this point the glider is no longer in contact with the spring....
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