problem06_60

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.60: a) kg. 7 . 41 m) (18.0 ) s m (9.80 J) 10 35 . 7 ( 2 3 g = × = - = = g s W g w m b) N. 458 m 0 . 18 J 10 25 . 8 3 n = × = = s W n c) The weight is N, 408 g = = s W mg so the acceleration is the net force divided by the
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Unformatted text preview: mass, . s m 2 . 1 kg 41.7 N 408 N 458 2 =-...
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