University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.64: a) From Eq. (6.7), - = - - = - = = 2 1 2 1 2 1 . 1 1 1 1 2 2 x x x x x x x x x k x k x dx k dx F W The force is given to be attractive, so 0 < x F , and k must be positive. If 1 2 1 1 1 2 , x x x x < , and 0 < W . b) Taking “slowly” to be constant speed, the net force on the object is zero, so the force applied by the hand is opposite
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Unformatted text preview: x F , and the work done is negative of that found in part (a), or ( 29 2 1 1 1 x x k-, which is positive if 1 2 x x . c) The answers have the same magnitude but opposite signs; this is to be expected, in that the net work done is zero....
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