This preview shows
page 1. Sign up
to
6.64:
a) From Eq. (6.7),
∫
∫
-
=
-
-
=
-
=
=
2
1
2
1
2
1
.
1
1
1
1
2
2
x
x
x
x
x
x
x
x
x
k
x
k
x
dx
k
dx
F
W
The force is given to be attractive, so
0
<
x
F
, and
k
must be positive. If
1
2
1
1
1
2
,
x
x
x
x
<
,
and
0
<
W
.
b) Taking “slowly” to be constant speed, the net force on the object is zero,
so the force applied by the hand is opposite
This is the end of the preview.
Sign up
to
access the rest of the document.
Unformatted text preview: x F , and the work done is negative of that found in part (a), or ( 29 2 1 1 1 x x k-, which is positive if 1 2 x x . c) The answers have the same magnitude but opposite signs; this is to be expected, in that the net work done is zero....
View
Full Document
