problem06_70

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.70: a) This is similar to Problem 6.64, but here 0 α (the force is repulsive), and 1 2 x x < , so the work done is again negative; J. 10 65 . 2 )) m 10 25 . 1 ( ) m 200 . 0 (( m N 10 12 . 2 ( 1 1 17 1 9 1 2 26 2 1 - - - - × - = × - × = - = x x W α Note that 1 x is so large compared to 2 x that the term 1 1 x is negligible. Then, using Eq. (6.13)) and solving for 2 v , . s / m 10 41 . 2 kg) 10 67 . 1 ( J) 10 65 . 2 ( 2 s) / m 10 00 . 3 ( 2 5 27 17 2 5 2 1 2 × = × × - + × = + = - - m W v v b) With 1 2 , 0 K W K - = = . Using 2 x W α - = ,
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