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**Unformatted text preview: **6.78: The work done by gravity is Wg = - mgL sin (negative since the cat is moving up), and the work done by the applied force is FL, where F is the magnitude of the applied force. The total work is Wtot = (100 N)(2.00 m) - (7.00 kg)(9.80 m / s 2 )(2.00 m) sin 30 = 131.4 J.
2 2 The cat's initial kinetic energy is 1 mv1 = 1 (7.00 kg )(2.40 m / s) = 20.2 J , and 2 2 v2 = 2( K1 + W ) = m 2(20.2 J + 131.4 J ) = 6.58 m / s. (7.00 kg) ...

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