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**Unformatted text preview: **43‘ g .V: 12,000v s) I= €ﬂ=625A ‘7 13:31?" 532m WWW ""7 W
.V= Soooov PJR
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! \ ‘ 10:0 ’4 WLQ A“): «Ar?!- ’04, Alﬁ) 5» crew linearly 25.26 Total resistance R = 3.70M) Temperature coeﬂicient of carbon: 0:0 2 70.005(C“’)_1
Temperature coefﬁcient of nichrome: aN : O.OO4(C")’1 R : R0 -|- RN
: Rcoﬂ —— aoAT) —|— RN0(1 + aNAT)
: ROM1 “ 050C? — Toll + RN0(1 + (EMT — TOD
: ROO(1 -- 050T) + RN0(1 —|— aNT) since To is 0 here
: R00 -|- RNO -|- (06011700 + aNRNolT If we want the total resistance to be temperature independent, we must have (101300 + CENRNO : 0 R
RNO : _ 00050
05N
Therefore a
R 2 R00 + Rm 2 (14 image 2 3.71m
GIN
plug in values for temperature coefﬁcients —> R00 : 1644.449
RNO : R — R00 : 2055.569
25.71 (a) 2
V
P = 7 R AP i P2 —P1 i Vgg/R—Vlg/R i V22 — V12 i 1052— 1172 i i 0.19 : 19
P1 P1 VIE/R V12 1172 % The negative sign indicates that the power output decreased. (b) The decrease in power leads to decrease in temperature, which means increase in
resistance. This means that the percentage change in power output would be less
than we calculated in part (a). ...

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- Spring '12
- welsch