S12_1252_Exam_2_Key

451 429103 1negativeslope 1positiveslope

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Unformatted text preview: +2 The catalyst is involved in the rate determining (slow) step, and therefore in the overall rate law. +2 4 3 A Energy 6. Consider the reaction 2 NO2(g) 2 NO(g) + O2(g), for which the following data were collected. +2 each box, all or nothing 4 (a) Identify the column headings for the following data used to find the integrated rate law. ln[NO2] 1/[NO2] (M­1) [NO2] (M) Time (s) 0 125 4.828 8.00 10‐3 50. 152 5.024 6.58 10‐3 100. 179 5.187 5.59 10‐3 150. 206 5.329 4.85 10‐3 200. 233 5.451 4.29 10‐3 +1 negative slope +1 positive slope +1 negative slope +1 curve +1 line +1 curve (b) Give a rough sketch of the shape of each of each column plotted against time on the 6 indicated diagrams. Note that your drawings do not have to be to scale. (c) Write the overall differential (d) From the data, calculate the value of k, including units. rate law for the reaction. 152 M‐1 = k(50. s)+ 125 M‐1 +2 integrated rate law used 2 +1 correct b, +1 y matches x rate = k[NO2] 2 k = 0.54 M‐1s...
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