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**Unformatted text preview: **. 3 2 3 2 4 ) ( 4 3 2 2 2 2 x F x x x x F dx x x x x F Fdx x x = -=-= With N 200 = F and J. 100 m, 75 . = = W x The speed of the arrow is then . s m 89 kg) (0.025 J) 100 ( 2 2 = = m W Other ways of finding the area under the curve in Fig. (6.28) should give similar results....

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