problem06_86

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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6.86: Your friend’s average acceleration is 2 0 m/s 00 . 2 s 3.00 m/s 00 . 6 = = - = t v v a Since there are no other horizontal forces acting, the force you exert on her is given by N 130 ) m/s kg)(2.00 0 . 65 ( 2 net = = = ma F Her average velocity during your pull is 3.00 m/s, and the distance she travels is thus 9.00

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Unformatted text preview: m. The work you do is J 1170 m) N)(9.00 130 ( = = Fx , and the average power is therefore W. 390 s J/3.00 1170 = The work can also be calculated as the change in the kinetic energy....
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