96 psift fracture gradients 111 24 fig 5 5 at 11000

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ft γ = 0.46 Fracture Gradients 1.11- 25 Example - Ben Eaton From above graphs, at 11,000 ft.: S = 0.96 D psi / ft; S P γ F = − D D 1 − γ P + D γ = 0.46 0.46 F = ( 0.96 − 0.735 ) + 0.735 1 − 0.46 F = 0.9267 psi/ft = 17.82 lb/gal Fracture Gradients 1.11- 26 Summary of Results Fracture Gradient psi.ft lb/gal Hubbert & Willis minimum: 0.823 15.83 Hubbert & Willis maximum: 0.868 16.68 Mathews & Kelly: 0.917 17.63 Ben Eaton: 0.927 17.82 Fracture Gradients 1.11- 27 Summary of Results 4 Note that all the methods take into consideration the pore pressure gradient. As the pore pressure increases, so does the fracture gradient. 4 In...
View Full Document

This note was uploaded on 09/18/2012 for the course ENGINEERIN 102 taught by Professor Clyde during the Spring '12 term at A.T. Still University.

Ask a homework question - tutors are online