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Unformatted text preview: PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS CLASS 8. 30.02, 30.03, 30.08, 30.22 30.02. a) mV . 7 . 12 mWb] ) . 7 . 6 [( 2 + = + = = t t t dt d dt d B E At t = 2.0 s, . 7 ) . 2 ( . 12 + = E mV E = 31 mV b) The flux is increasing, so Lenzs law tells us that the field produced by the induced current must point into the page to oppose the increase. The current must flow clockwise around the circuit, or: to the left in resistor R . 30.03. dt dB r dt dB r dt d r B BA dt d B B B 2 2 2 and , so , where , - = = = = - = E E mV 11 Then, s. / T 25 . s . 4 s . 6 T 5 . T . s, 6 < < s 4 For c) mV . Then, s. / T . s . 2 s . 4 T 5 . T 5 . s, 4 < < s 2 For b) mV 11 Then, s. / T 25 . s . s . 2 T . T 5 . s, 2 < < For a) T) / s mV 45 ( T) / s V 045 . ( ) m 12 . ( Then, 2 =- =-- = = =-- =- = =-- = - = - =- = E E E E dt dB t dt dB t dt dB t dt dB dt dB dt dB 30.08. The field (due to the current in the straight wire) is out-of-the-page in the upper half of the circle and is into the page in the lower half of the circle. Due to the symmetry, the the circle and is into the page in the lower half of the circle....
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