problem06_99

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
6.99: a) N. 358 km/h)) m/s)/(3.6 km/h)((1 0 . 60 ( W/hp) hp)(746 00 . 8 ( = b) The extra power needed is hp, 2 . 39 kW 3 . 29 )) 10 / 1 ( sin(arctan 3.6 km/h 6 . 60 ) m/s kg)(9.80 1800 ( m/s km/h 2 || = = = mgv so the total power is 47.2 hp. (Note: If the sine of the angle is approximated by the tangent, the third place will be different.) c) Similarly, hp, 94 . 3 kW 94 . 2 )) 010 . 0 ( sin(arctan 3.6 km/h 0 . 60 ) m/s kg)(9.80 1800 ( m/s km/h 2 || = = = mgv This is the rate at which work is done on the car by gravity. The engine must do work on
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: the car at a rate of 4.06 hp. d) In this case, approximating the sine of the slope by the tangent is appropriate, and the grade is , 0203 . km/h)) m/s)/(3.6 km/h)((1 . 60 )( m/s kg)(9.80 1800 ( W/hp) hp)(746 00 . 8 ( 2 = very close to a 2% grade....
View Full Document

This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online