hw10 - PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS CLASS 10. 30.34, 30.39, 30.44; Q32.01, Q32.03 30.34. path 1: dt d s d E B 1 1 Φ- = ⋅ ∫ . Since the integration path is counter clockwise, the positive direction for flux or magnetic field is out of the page. Therefore, the magnetic field is in the negative direction. Since the magnetic field is decreasing in magnitude, dt dB 1 is positive. Then, dt dB r dt dB A dt A B d dt d s d E B 1 2 1 1 1 1 1 1 1 ) ( π- =- =- = Φ- = ⋅ ∫ T/s) 10 50 . 8 ( m) 200 . ( 3 2 1 2 1 1- ×- =- = ⋅ ∫ π π dt dB r s d E V 10 07 . 1 3 1- ×- = ⋅ ∫ s d E path 2: dt d s d E B 2 2 Φ- = ⋅ ∫ . Since the integration path is clockwise, the positive direction for flux or magnetic field is into the page. Therefore, the magnetic field is in the negative direction. Since the magnetic field is decreasing in magnitude, dt dB 2 is positive. Then, dt dB r dt dB A dt A B d dt d s d E B 2 2 2 2 2 2 2 2 2 ) ( π- =- =...
View Full Document

This note was uploaded on 04/07/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

Page1 / 2

hw10 - PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online