# hw04 - PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS...

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Unformatted text preview: PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS CLASS 4. 25.03, 25.23, 25.67; Q26.02, Q26.05 25.03. pF 144 F 10 44 . 1 m 10 30 . 1 m) (0.0820 m) / F 10 85 . 8 ( a) 10 3 2 12 2 = × = × × = = =--- C d r d A C π π ε ε b) Q = CV = (1.44 × 10-10 F)(120 V) Q = 1.73 × 10-8 C = 17.3 nC 25.23. When only switch S 1 is closed, The series combination of C 1 and C 3 is connected across the battery, as is the series combination of C 2 and C 4 . Consider each series combination separately. For C 1 and C 3 , the charge on each capacitor is the same, and equal to the charge on the series combination. Calculate the capacitance of the series combination, and then calculate the charge on the combination. 3 1 3 1 13 C C C C C + = , so C 9.00 V) . 12 ( F 00 . 3 F 00 . 1 F) 00 . 3 F)( 00 . 1 ( 3 1 3 1 13 13 μ μ μ μ μ = + = + = = V C C C C V C q Do the same for C 2 and C 4 . 4 2 4 2 24 C C C C C + = , so C 16.0 V) . 12 ( F 00 . 4 F 00 . 2 F) 00 . 4 F)( 00 . 2 ( 4 2 4 2 24 24 μ μ μ μ μ =...
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## This note was uploaded on 04/07/2008 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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hw04 - PHYS-1200 PHYSICS II SPRING 2006 HOMEWORK SOLUTIONS...

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