200_Lectures_11_21_post

8 r t m rt v mp pv m va va mp v rt 4 2 1

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Unformatted text preview: lbmol − o R lbm lbmol ) ( 50 lb f in ) (80 + 459.67 ) 2 o ) 144in 2 1 ft 2 R mN2 = 0.021 lbm s % ' ( +! 5, - = 6+ v ( 80o F ,50 psia ) = 1.2716 ft 4 π ft m= s 1 ft 2in 4 12in 1.2716 ft mR − 22 = 0.069 ( G! ! %0 ! 0 % lbm A #=9 1.' 3 lbm 2 3 lbm s !* ! , ! % %0 E * time rate of change of the energy contained within the control volume at time t ! "# % net rate at which energy is being transferred out by work at time t net rate at which energy is being transferred in by heat transfer at time t net rate of energy transfer into the control volume accompanying mass flow $ ' () ( dE CV =Q−W+ dt & +" - "% "( ( ( ( min ein − m out eout in *% & out , ( " . % , /( % + 0 p v area A L ' " (% 2 e = u + ke + pe & "( 1" " & "& ( " (% 3 45 5 67 ( % ( " ( 69 4 4 @$ 8 *1@ * . @ $69 8 * . "" 8 $ 1" %" 6$ 9 $ 8* 8$ " "( + $ ( > * @ @$ * 1 @ 69 * @ * @ $7 A 8 & ∆ ; <8 :* ∆" ; <8 :* B C 4 * ; +: & "& (% 4? ( D " & 4 / * %" * ( $ ( " (( % & : " ; <8 := : "...
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This note was uploaded on 09/22/2012 for the course ME 200 taught by Professor Gal during the Spring '08 term at Purdue University.

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