University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
7.2: a) For constant speed, the net force is zero, so the required force is the sack’s weight, N. 49 ) s m kg)(9.80 00 . 5 ( 2 = b) The lifting force acts in the same direction as the sack’s motion, so the work is equal to the weight times the distance,
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: J; 735 m) (15.0 N) 00 . 49 ( = this work becomes potential energy. Note that the result is independent of the speed, and that an extra figure was kept in part (b) to avoid roundoff error....
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online