problem07_06

# University Physics with Modern Physics with Mastering Physics (11th Edition)

This preview shows page 1. Sign up to view the full content.

7.6: a) (Denote the top of the ramp as point 2.) In Eq. (7.7), J, 5 . 87 m) (2.5 N) 35 ( , 0 other 2 - = × - = = W K and taking 0 1 = U and s, m 25 . 6 J, 147 ) 30 sin m (2.5 ) s m (9.80 kg) 12 ( kg 12 J) 5 . 87 J 147 ( 2 1 2 2 2 = = = ° = = + v mgy U or s m 3 . 6 to two figures. Or, the work done by friction and the change in potential energy are both proportional to the distance the crate moves up the ramp, and so the initial speed
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: is proportional to the square root of the distance up the ramp; . s m 25 . 6 s) m . 5 ( m 1.6 m 2.5 = b) In part a), we calculated other W and 2 U . Using Eq. (7.7), J 491.5 J 147 J 5 . 87 s) m (11.0 kg) 12 ( 2 2 1 2 =--= K . s m 05 . 9 kg) 12 ( J) 5 . 491 ( 2 2 2 2 = = = m K v...
View Full Document

## This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online