2 400 1571 kn 800 b f b2 3142 400 1571 kn and h2

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Unformatted text preview: haft for the two positions of the crank, i.e. firstly when the crank is at the dead centre ; and secondly when the crank is at an angle of maximum twisting moment. Part of a car engine 1. Design of the crankshaft when the crank is at the dead centre (See Fig. 32.18) We know that the piston gas load, π π × D 2 × p = (400)2 2.5 = 314 200 N = 314.2 kN 4 4 Assume that the distance (b) between the bearings 1 and 2 is equal to twice the piston diameter FP = (D). ∴ b = 2D = 2 × 400 = 800 mm Internal Combustion Engine Parts n 1177 b 800 = = 400 mm 2 2 We know that due to the piston gas load, there will be two horizontal reactions H1 and H2 at bearings 1 and 2 respectively, such that and b1 = b2 = FP × b1 314.2 × 400 = = 157.1 kN 800 b F × b2 314.2 × 400 = = 157.1 kN and H2 = P 800 b Assume that the length of the main bearings to be equal, i.e. c1 = c2 = c / 2. We know that due to the weight of the flywheel acting downwards, there will be two vertical reactions V2 and V3 at bearings 2 and 3 respectively, such that H1 = V2 =...
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This note was uploaded on 09/30/2012 for the course MECHANICAL 403 taught by Professor A.thirumoorthy during the Spring '11 term at Anna University Chennai - Regional Office, Coimbatore.

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