# 3222 valve gear mechanism the valve gear mechanism of

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Unformatted text preview: 6 )2 + (4.5 ×106 )2 = 7.66 × 10 N-mm We also know that equivalent twisting moment (Te), Te = π π (d s1 )3 τ = (180)3 τ = 1.14 × 106 τ ...(Taking ds1 = d1) 16 16 ∴ τ = 7.66 × 106 / 1.14 × 106 = 6.72 N/mm2 or MPa Since the induced shear stress is less than the permissible limit of 30 to 40 MPa, therefore, the design is safe. (c) Design of shaft under the flywheel Let ds = Diameter of shaft under the flywheel. We know that horizontal bending moment acting on the shaft due to piston gas load, 7.66 × 106 = MH = FP (a + b2 ) − ( H R1 ) 2 + ( H T1 ) 2 b2 470 32 3 2 470 = 44 200 239 + 2 − (49.8 × 10 ) + (45 × 10 ) 2 6 – 15.77 × 106 = 5.18 × 10 6 N-mm = 20.95 × 10 and bending moment due to the flywheel weight Internal Combustion Engine Parts MV = n 1189 W .b1 . b2 30 × 103 × 235 × 235 = = 3.53 × 106 N-mm 470 b ...(b1 = b2 = b / 2 = 470 /2 = 235 mm) ∴ Resultant bending moment, ( M H ) 2 + ( M V )2 = = 6.27 × 106 N-mm We know that twisting moment on the shaft, MR = (5.18 × 106 )2 + (3.53 × 106 )2 T = FT × r = 30 ×...
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## This note was uploaded on 09/30/2012 for the course MECHANICAL 403 taught by Professor A.thirumoorthy during the Spring '11 term at Anna University Chennai - Regional Office, Coimbatore.

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