# 6 piston pin let d0 outside diameter of the pin in mm

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Unformatted text preview: rom above, we find that 45 l = 3928 or l = 3928 / 45 = 87.3 say 90 mm Ans. ∴ Total length of the piston , L = Length of the skirt + Length of the ring section + Top land = l + (4 t2 + 3b2) + b1 = 90 + (4 × 3 + 3 × 3) + 18 = 129 say 130 mm Ans. 6. Piston pin Let d0 = Outside diameter of the pin in mm, l1 = Length of pin in the bush of the small end of the connecting rod in mm, and Internal Combustion Engine Parts n 1143 pb1 = Bearing pressure at the small end of the connecting rod bushing in N/mm2. It value for bronze bushing is taken as 25 N/mm2. We know that load on the pin due to bearing pressure = Bearing pressure × Bearing area = pb1 × d0 × l1 = 25 × d0 × 0.45 × 100 = 1125 d0 N ...(Taking l1 = 0.45 D) We also know that maximum load on the piston due to gas pressure or maximum gas load = π D2 π (100) 2 ×p= × 5 = 39 275 N 4 4 From above, we find that 1125 d0 = 39 275 or d0 = 39 275 / 1125 = 34.9 say 35 mm Ans. The inside diameter of the pin (di) is usually taken as 0.6 d0. ∴ di = 0.6 ×...
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