Assume that the width of flywheel is 250 mm and l1 l2

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Unformatted text preview: know that bending moment at the centre of the bearing 1, M = FP (0.75lc + t + 0.5 l1) = 103 × 103 (0.75 × 92 + 70 + 0.5 × 200) = 24.6 × 106 n-mm We also know that bending moment (M), 24.6 × 106 = π π (d )3 σ = (d )3 60 = 5.9 (d1 )3 32 1 b 32 1 ...(Taking σb = 60 MPa or N/mm2) ∴ (d1 = 24.6 × /5.9 = 4.2 × or d1 = 161.3 mm say 162 mm Ans. (c) Design of crank web Let w = Width of the crank web in mm. We know that bending moment on the crank web, M = FP (0.75lc + 0.5 t) = 103 × 103 (0.75 × 92 + 0.5 × 70) = 10.7 × 106 N-mm )3 106 106 1 1 × w · t 2 = × w (70)2 = 817 w mm3 6 6 10.7 × 106 13 × 103 M σb = = = ∴ Bending stress, N/mm2 817 w Z w and direct compressive stress, FP 103 ×103 1.7 × 103 = = σb = N/mm2 w .t w × 70 w We know that total stress on the crank web, and section modulus, Z= 13 × 103 1 .7 × 1 0 3 1 4 .4 7 × 1 0 3 N/mm2 + = w w w The total stress should not exceed the permissible limit of 60 MPa or N/mm2. σT = σb + σd = 14.47 ×103 14.47 × 103 or w = = 241...
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This note was uploaded on 09/30/2012 for the course MECHANICAL 403 taught by Professor A.thirumoorthy during the Spring '11 term at Anna University Chennai - Regional Office, Coimbatore.

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