# From fig 3210 we see that force in the connecting rod

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Unformatted text preview: be taken into consideration, then FP = FL ∓ F1 ± WR * Acceleration of reciprocating parts = ω2 · r cos θ + cos 2θ n Internal Combustion Engine Parts n 1147 The force FP gives rise to a force FC in the connecting rod and a thrust FN on the sides of the cylinder walls. From Fig. 32.10, we see that force in the connecting rod at any instant, * FP FP FC = c os φ = sin 2 θ 1− n2 The force in the connecting rod will be maximum when the crank and the connecting rod are perpendicular to each other (i.e. when θ = 90°). But at this position, the gas pressure would be decreased considerably. Thus, for all practical purposes, the force in the connecting rod (FC) is taken equal to the maximum force on the piston due to pressure of gas (FL), neglecting piston inertia effects. 2. Force due to inertia of the connecting rod or inertia bending forces Consider a connecting rod PC and a crank OC rotating with uniform angular velocity ω rad / s. In order to find the accleration of various points on the connecting rod, draw the Klien’s acceleration diagram CQNO as shown in Fig. 32.11 (a...
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