# CH-32

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Unformatted text preview: diameter of the screw, dc 8 = = 9.52 say 10 mm Ans. d= 0.84 0.84 We shall use 10 mm stud and it is provided with a lock nut. The diameter of the circular end of the arm (D3) and its depth (t4) is taken as twice the diameter of stud. ∴ D3 = 2 × 10 = 20 mm Ans. and t4 = 2 × 10 = 20 mm Ans. 5. Design for valve spring First of all, let us find the total load on the valve spring. We know that initial load on the spring, W1 = Initial spring force (Fs) = 96.6 N ...(Already calculated) and load at full lift, W2 = Full valve lift × Stiffiness of spring (s) ...(Assuming s = 10 N/mm) = 25 × 10 = 250 N ∴ Total load on the spring, W = W1 + W2 = 96.6 + 250 = 346.6 N Now let us find the various dimensions for the valve spring, as discussed below: (a) Mean diameter of spring coil Let D = Mean diameter of the spring coil, and d = Diameter of the spring wire. We know that Wahl’s stress factor, K= 4C − 1 0.615 4 × 8 − 1 0.615 + = + = 1.184 4C − 4 C 4×8− 4 8 ...(Assuming C = D/d = 8) and maximum shear stress...
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## This note was uploaded on 09/30/2012 for the course MECHANICAL 403 taught by Professor A.thirumoorthy during the Spring '11 term at Anna University Chennai - Regional Office, Coimbatore.

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