We know that bending moment at the juncture of the

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ft in mm. We know that bending moment on the shaft, MS = R3 × c1 and twisting moment on the shaft, TS = FT × r ∴ Equivalent twisting moment on the shaft, Te = ( M S ) 2 + (TS ) 2 = ( R3 × c1 ) 2 + ( FT × r ) 2 ... (i) We also know that equivalent twisting moment on the shaft, π ( d )3 τ 16 s τ = Allowable shear stress in the shaft. Te = where ... (ii) From equation (i) and (ii), the diameter of the shaft is determined. (c) Design of shaft at the juncture of right hand crank arm Let ds1 = Diameter of the shaft at the juncture of right hand crank arm. We know that bending moment at the juncture of the right hand crank arm, l t t l MS1 = R1 b 2 + c + − FQ c + 2 2 2 2 and the twisting moment at the juncture of the right hand crank arm, TS1 = FT × r ∴ Equivalent twisting moment at the juncture of the right hand crank arm, Te = ( M S1 ) 2 + (TS1 ) 2 ... (i) We also know that equivalent twisting moment, π (d )3 τ ... (ii) 16 s1 where τ = Allowable shear stress in the shaft. From equations (i) and (ii), the diameter of the shaft at the juncture of the right hand crank arm is determined. (d) Design of right hand crank web The right hand crank web is subjected to the follo...
View Full Document

Ask a homework question - tutors are online