University Physics with Modern Physics with Mastering Physics (11th Edition)

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7.17: a) Solving Eq. (7.9) for m. 063 . 0 , m) N 1600 ( J) 20 . 3 ( 2 2 = = = k U x x b) Denote the initial height of the book as h and the maximum compression of the spring by x . The final and initial kinetic energies are zero, and the book is initially a height h x + above the point where the spring is maximally compressed. Equating initial and final potential energies, ). ( 2 2 1 h x mg kx + = This is a quadratic in x , the solution to
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Unformatted text preview: which is m. 101 . m, 116 . ) s m (9.80 kg) (1.20 m) (0.80 m) N 1600 ( 2 1 1 m) N 1600 ( ) s m kg)(9.80 20 . 1 ( 2 1 1 2 2-= + ± = + ± = mg kh k mg x The second (negative) root is not unphysical, but represents an extension rather than a compression of the spring. To two figures, the compression is 0.12 m....
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  • Kinetic Energy, initial kinetic energies, final potential energies

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