problem07_20

University Physics with Modern Physics with Mastering Physics (11th Edition)

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7.20: As in Example 7.8, 1 0 K = and J. 0250 . 0 1 = U For s, m 20 . 0 2 = v J, 0040 . 0 2 = K so , J 0210 . 0 2 2 1 2 kx U = = so m. 092 . 0 m N 5.00 J) 0210 . 0 ( 2 ± = ± = x In the absence of friction, the glider will go through the equilibrium position and pass through
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Unformatted text preview: m 092 .-= x with the same speed, on the opposite side of the equilibrium position....
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