problem07_45

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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7.45: a) J 9 . 15 ) m 50 . 2 )( s m 80 . 9 )( kg 650 . 0 ( 2 = = mgh b) The second height is , m 875 . 1 ) m 50 . 2 ( 75 . 0 = so second ; J 9 . 11 = mgh loses J 4.0 J 11.9 J 9 . 15 = - on first bounce. This energy is converted to thermal energy. a)
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Unformatted text preview: The third height is , m 40 . 1 ) m 875 . 1 ( 75 . = , so third ; J 9 . 8 = mgh loses J 3.0 J 8.9 J 9 . 11 =-on second bounce....
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