problem07_52

University Physics with Modern Physics with Mastering Physics (11th Edition)

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7.52: For the skier to be moving at no more than s m 0 . 30 ; his kinetic energy at the bottom of the ramp can be no bigger than J 250 , 38 2 ) s m 0 . 30 )( kg 0 . 85 ( 2 2 2 = = mv Friction does J 4000 - of work on him during his run, which means his combined PE and KE at the top of the ramp must be no more than J. 42,250 J 4000 J 250 , 38 = + His KE
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Unformatted text preview: at the top is J 170 2 ) s m . 2 )( kg . 85 ( 2 2 2 = = mv His PE at the top should thus be no more than , J 42,080 J 170 J 250 , 42 =-which gives a height above the bottom of the ramp of . m 5 . 50 ) s m 80 . 9 )( kg . 85 ( J 080 , 42 J 080 , 42 2 = = = mg h...
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