problem07_52

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
7.52: For the skier to be moving at no more than s m 0 . 30 ; his kinetic energy at the bottom of the ramp can be no bigger than J 250 , 38 2 ) s m 0 . 30 )( kg 0 . 85 ( 2 2 2 = = mv Friction does J 4000 - of work on him during his run, which means his combined PE and KE at the top of the ramp must be no more than J. 42,250 J 4000 J 250 , 38 = + His KE
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: at the top is J 170 2 ) s m . 2 )( kg . 85 ( 2 2 2 = = mv His PE at the top should thus be no more than , J 42,080 J 170 J 250 , 42 =-which gives a height above the bottom of the ramp of . m 5 . 50 ) s m 80 . 9 )( kg . 85 ( J 080 , 42 J 080 , 42 2 = = = mg h...
View Full Document

This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online