problem07_62

University Physics with Modern Physics with Mastering Physics (11th Edition)

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7.62: a) The skier’s kinetic energy at the bottom can be found from the potential energy at the top minus the work done by friction, J, 500 . 10 ) m 0 . 65 )( kg N 8 . 9 )( kg 0 . 60 ( F 1 - = - = W mgh K or J 720 , 27 J 500 , 10 J 200 , 38 1 = - = K . Then s m 4 . 30 kg 60 ) J 20 7 , 27 ( 2 2 1 = = = m K v . b) × - = + - = + - + ) N 588 )( 2 [(. J 720 , 27 ), ( J 720 , 27 ) ( 2 air k A F 1 2 K d f mgd W W K K μ )], m 82 )( N 160 ( ) m 82 ( + , or J 4957 J 763 , 22
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Unformatted text preview: J 720 , 27 2 =-= K . Then, . s m 9 . 12 s m 85 . 12 kg 60 ) J 4957 ( 2 2 2 = = = m K v c) Use the Work-Energy Theorem to find the force. , KE W = . N 2000 N 1983 ) m 5 . 2 ( ) J 4957 ( = = = d KE F...
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This document was uploaded on 02/04/2008.

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