Conclude association between x and y h there is anh

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Unformatted text preview: 59324: .102897, 0,(.Ha :82) = = 637123. = (−| .4127033 82)/ 1 − (Hniversity 2 Ha . Columbia −0 otherwise −Concludeassociation = 2.637123. If t 4. is no t(.. b. H0 : There102897, Ha995; 82)between X and |Y∗ | ≤ 2.637123 conclude H0 , otherwise Ha . Conclude association between X and Y H : There is anH . 2.49. aa. -0.4259324 a √ −0.4259324 ∗ 58 ∗ ∗ = H0 : There = −4. between t(0.995 2.49. t a.b. -0.4259324 is no association 263013. X and ,Y 80) = 2.637123. If |t | ≤ 2 1 − (−0.4259324) H likelihood association between X more Y : There and √ b. 2b. H0 :aconclude is an association between X Conclude Ha .working with loge L: MaximumThere is noestimators can...
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