Unformatted text preview: E x U = ± ) ( , where ± x are the extreme points of the motion. Rather than solve a quadratic, note that k F k F x k 2 2 2 1 ) (, so E x U = ± ) ( becomes , 2 2 1 2 2 k F k F x k F k F k F x k ± == ± ± . 3 k F x k F x= =+ f) The maximum kinetic energy occurs when ) ( x U is a minimum, the point k F x = found in part (b). At this point k F k F k F U E K 2 2 2 2 ) ( ) ( === , so mk F v 2 = ....
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 Energy, Kinetic Energy, Potential Energy, 2 K, stable point., 2 2 1 k

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