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Lab Report 8 - John Xu Lab Report Experiment 9 Preparation...

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John Xu 4/20/07 Lab Report Experiment 9: Preparation of a High-Temperature Superconductor 1. Calculations Trial 1 Moles of I - = (0.16 M KI)(0.040 L) = 0.0064 moles Total Volume: 0.060 L Concentration of I - : 0.0064 moles / 0.060 L = 0.11 M Moles of S 2 O 8 2- = (0.12 M (NH 4 ) 2 S 2 O 8 )(0.005 L) = 6.0 x 10 -4 moles Total Volume: 0.040 L Concentration of S 2 O 8 2- : 6.0 x 10 -4 moles / 0.040 L = 0.015 M Rate of Reaction: 5.5 x 10 -5 moles/L in 560 seconds = 9.8 x 10 -8 moles/L/s Trial 2 Moles of I - = (0.16 M KI)(0.040 L) = 0.0064 moles Total Volume: 0.060 L Concentration of I - : 0.0064 moles / 0.060 L = 0.11 M Moles of S 2 O 8 2- = (0.12 M (NH 4 ) 2 S 2 O 8 )(0.010 L) = 0.0012 moles Total Volume: 0.040 L Concentration of S 2 O 8 2- : 0.0012 moles / 0.040 L = 0.030 M Rate of Reaction: 5.5 x 10 -5 moles/L in 258 seconds = 2.1 x 10 -7 moles/L/s Trial 3 Moles of I - = (0.16 M KI)(0.040 L) = 0.0064 moles Total Volume: 0.060 L Concentration of I - : 0.0064 moles / 0.060 L = 0.11 M Moles of S 2 O 8 2- = (0.12 M (NH 4 ) 2 S 2 O 8 )(0.020 L) = 0.0024 moles Total Volume: 0.040 L Concentration of S 2 O 8 2- : 0.0012 moles / 0.040 L = 0.060 M Rate of Reaction: 5.5 x 10 -5 moles/L in 118 seconds = 4.7 x 10 -7 moles/L/s
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Trial 4 Moles of I - = (0.16 M KI)(0.005 L) = 8.0 x 10 -4 moles Total Volume: 0.025 L Concentration of I - : 8.0 x 10 -4 moles / 0.025 L = 0.032 M
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