problem08_06

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.6: From Eq. (8.2), ( 29 ( 29 s, m kg 015 . 1 s m 00 . 7 kg 145 . 0 - = - = y p and ( 29 ( 29 s, m kg 405 . 0 s m 00 . 9 kg 045 . 0 = = x p so the total momentum has magnitude ( 29 ( 29 s, m kg 09 . 1 s m kg 015 . 1 s m kg 405 . 0 2 2 2 2 = - + - = + = y x p p p and is at an angle arctan
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Unformatted text preview: ( 29 °-= +-68 405 . 015 . 1 , using the value of the arctangent function in the fourth quadrant ( 29 . p , y < x p...
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This document was uploaded on 02/04/2008.

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