Final_Exam_C_key - Chem 6A Section D 2011(Sailor Final Exam...

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Chapter 17 / Exercise 124
Chemistry
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Chem 6A Section D, 2011 (Sailor) Final Exam 1 INSTRUCTIONS: (1) Write your name in the blank titled "NAME" on the scantron form provided. (2)Write your section number in the blank titled "SUBJECT" on the scantron form. (3)Write your Student ID number in the blanks titled "ID NUMBER" on the scantron form. Use “1” in place of the “A” in your ID number. (4) Fill in BOX Cin the "TEST FORM" box on the scantron form. (5)Perform all your scratch work on this test. You can take it with you at the end of the exam. You are allowed to use a calculator and one 5x8 index card of notes (both sides). 11812H21314151617He1.00794.0026345678910LiBeBCNOFNe6.9419.0121810.81112.01114.006715.999418.998420.17971112131415161718NaMg3456789101112AlSiPSClAr22.989824.30526.981528.085530.973832.06635.452739.948192021222324252627282930313233343536KCaScTiVCrMnFeCoNiCuZnGaGeAsSeBrKr39.098340.07844.955947.8850.941551.996154.938155.84758.933258.6963.54665.3969.72372.6174.921678.9679.90483.8373839404142434445464748495051525354RbSrYZrNbMoTcRuRhPdAgCdInSnSbTeIXe85.457887.6288.905991.22492.906495.9498.9063101.07102.906106.42107.868112.411114.82118.71121.75127.6126.905131.29555657727374757677787980818283848586CsBaLaHfTaWReOsIrPtAuHgTlPbBiPoAtRn132.905137.327138.906178.49180.948183.85186.207190.2192.22195.08196.967200.59204.383207.2208.98208.982209.987222.018878889104105106107108109FrRaAc223.02226.025227.028 ------5859606162636465666768697071LanthanidesCePrNdPmSmEuGdTbDyHoErTmYbLu140.12140.91144.24146.92150.35151.96157.25158.92162.5164.93167.26168.93173.04174.9790919293949596979899100101102103ActinidesThPaUNpPuAmCmBkCfEsFmMdNoLr232.038231.04238.03237.05239.05241.06247.07249.08251.08254.09257.1258.1255262.1Some useful constants and relationships:Specific heat capacities (in J/g.K): H2O(l) = 4.184; Al(s)= 0.900; Cu(s)= 0.387; Steel(s)= 0.45 101.325 J = 1 L.atm 1 atm = 760 Torr 1J = 1kg.m2/s21 eV = 1.6022 x 10-19J R = Ideal gas constant: 0.08206 L.atm.mol-1 .K-1= 8.31451 J.mol-1 .K-1 Avogadro constant: 6.022 x 1023mole-1 Planck's constant = h = 6.6261 x 10-34J.s c = speed of light: 3.00 x 108m/s RH= 1.097 x 10-2nm-1C2= second radiation constant = 1.44 x 10-2K.m Tλmax=15C2Emitted power (W)Surface area (m2)=(constant)T4e=mc2c=λν1λ=RH1n121n22ΛΝΜΞΠΟE=hνE=hcλE(in Joules)=2.18×1018Z2n2ΛΝΜΞΠΟ
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Chapter 17 / Exercise 124
Chemistry
Zumdahl
Expert Verified
Chem 6A Section D, 2011 (Sailor) Final Exam 2 1. Given the thermochemical data below, calculate Hrxnfor the reaction CaCO3(s)CaO(s)+ CO2(g)Hrxn= ? +178.3 kJ Process Enthalpy, kJCa(s)+ ½O2(g)CaO(s)Hrxn= -635.1 Ca2+(g)+ 2e-Ca(g)Hrxn= -1735 C(s) + O2(g)CO2(g)Hrxn= -393.5 Ca(s)+ ½O2(g) + CO2(g)CaCO3(s)Hrxn= -813.4 Ca(s)+ S(s)CaS(s)Hrxn= -482
2. Which of the following is the most plausible structure for the PCl4+ion:
c)

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